Odpowiedź :
[tex]x {y}^{2} - xy = - 0.3 \times {1}^{2} - ( - 0.3) \times 1 = - 0.3 - ( - 0.3) = - 0.3 + 0.3 = 0[/tex]
[tex]2x - {y}^{2} = 2 \times 5 - ({ - 3)}^{2} = 10 - 9 = 1[/tex]
[tex]x {y}^{2} - xy = - 0.3 \times {1}^{2} - ( - 0.3) \times 1 = - 0.3 - ( - 0.3) = - 0.3 + 0.3 = 0[/tex]
[tex]2x - {y}^{2} = 2 \times 5 - ({ - 3)}^{2} = 10 - 9 = 1[/tex]