[tex]\frac{3}{13}+\frac{4}{13}=\frac{7}{13}\\\\\frac{5}{10}+\frac{19}{10}=\frac{24}{10}=2\frac{4}{10}=2\frac{2}{5}\\\\2\frac{1}{3}+5\frac{2}{3}=7\frac{3}{3}=8\\\\3\frac{3}{7}+2\frac{6}{7}=5\frac{9}{7}=6\frac{2}{7}\\\\1-\frac{5}{9}=\frac{9}{9}-\frac{5}{9}=\frac{4}{9}\\\\11\frac34-8\frac14=3\frac24=3\frac12\\\\6-1\frac{1}{5}=5\frac{5}{5}-1\frac{1}{5}=4\frac{4}{5}\\\\12\frac35-6\frac45=11\frac85-6\frac45=5\frac45[/tex]
