Odpowiedź :
[tex]Zadanie\\\\\frac{x-1}{2x-3}=5\ \ \ \mid\cdot(2x-3)\\\\x-1=5(2x-3)\\\\x-1=10x-15\ \ \ \mid+1 \\\\x=10x -14\ \ \ \mid-10x\\\\-9x=-14\ \ \ \mid:(-9)\\\\x= \frac{14}{9}\\\\x=1\frac{5}{9}[/tex]
[tex]Zadanie\\\\\frac{x-1}{2x-3}=5\ \ \ \mid\cdot(2x-3)\\\\x-1=5(2x-3)\\\\x-1=10x-15\ \ \ \mid+1 \\\\x=10x -14\ \ \ \mid-10x\\\\-9x=-14\ \ \ \mid:(-9)\\\\x= \frac{14}{9}\\\\x=1\frac{5}{9}[/tex]