Odpowiedź:
b) [tex]\frac{\sqrt{5} *\sqrt{18} * \sqrt{40} }{\sqrt[3]{12} * \sqrt[3]{9} * \sqrt[3]{2} }[/tex] = [tex]\frac{\sqrt{3600}}{\sqrt[3]{216}} = \frac{60}{6} = 10\\[/tex]
c) [tex]\sqrt[3]{2\frac{22}{25} } : \sqrt[3]{\frac{5}{24} } = \sqrt[3]{\frac{72}{25} : \frac{5}{24}} = \sqrt[3]{\frac{72}{25} * \frac{24}{5} } = \sqrt[3]{ \frac{1728}{125} } = \frac{12}{5}[/tex]
