[tex]dane:\\M_{z} = 6\cdot10^{24} ] kg\\m = 55 \ kg\\R = 6370 \ km = 6,37\cdot10^{6} \ m\\G = 6,67\cdot10^{-11}\frac{Nm^{2}}{kg^{2}}\\szukane:\\F = ?\\\\Rozwiazanie\\\\F = G\cdot\frac{M_{z}m}{R^{2}}\\\\F = 6,67\cdot10^{-11}\frac{Nm^{2}}{kg^{2}}\cdot\frac{6\cdot10^{24} \ kg\cdot55 \ kg}{(6,37\cdot10^{6}m)^{2}}= \frac{2201,1\cdot10^{13}}{40,5769\cdot10^{12}} \ N= 54,245\cdot10 \ N = 542,45 \ N[/tex]
