Odpowiedź :
2 C3H8 + 7 O2 ----> 6 CO + 8H2O
MC3H8= 3*12+ 8*1= 36+8=44 g/mol
MCO=12+16=28 g/mol
2*44 g C3H8-------- 6*28 g CO
x. -------- 100 g CO
x= 52,38 g C3H8
2 C3H8 + 7 O2 ----> 6 CO + 8H2O
MC3H8= 3*12+ 8*1= 36+8=44 g/mol
MCO=12+16=28 g/mol
2*44 g C3H8-------- 6*28 g CO
x. -------- 100 g CO
x= 52,38 g C3H8