Odpowiedź :
pole koła
[tex]p = \pi {r}^{2} \\ 36\pi = \pi {r}^{2} \\ {r}^{2} = 36 \\ r = 6 \\ \\ d = 2r \\ d = 2 \times 6 = 12[/tex]
odp. B
pole koła
[tex]p = \pi {r}^{2} \\ 36\pi = \pi {r}^{2} \\ {r}^{2} = 36 \\ r = 6 \\ \\ d = 2r \\ d = 2 \times 6 = 12[/tex]
odp. B