[tex]\frac{x+2^{0} }{3} -\frac{3(2x-\sqrt{16}) }{2}= \frac{4x^{0} }{\sqrt[3]{27} } -\frac{x}{6\\}[/tex]
[tex]\frac{x+1}{3} -\frac{3(2x-4x)} {2} = \frac{1}{3} - \frac{x}{6}[/tex]
[tex]\frac{x+1}{3} -\frac{3(-2x)} {2} = \frac{1}{3} - \frac{x}{6}[/tex]
[tex]\frac{x+1}{3} -\frac{6x} {2} = \frac{1}{3} - \frac{x}{6}[/tex]
2(x+1)+18x=2-x
2x+2+18x=2-x
2x+18x=-x
20x=-x
20x+x=0
21x=0
x=0
