Odpowiedź :
[tex]dane:\\F = 1000 \ N\\S = 2 \ m^{2}\\szukane:\\p = ?\\\\p = \frac{F}{S}\\\\p = \frac{1000 \ N}{2 \ m^{2}}\\\\p = 500\frac{N}{m^{2}} = 500 \ Pa[/tex]
Odp. Wywiera ciśnienie p = 500 Pa.
[tex]dane:\\F = 1000 \ N\\S = 2 \ m^{2}\\szukane:\\p = ?\\\\p = \frac{F}{S}\\\\p = \frac{1000 \ N}{2 \ m^{2}}\\\\p = 500\frac{N}{m^{2}} = 500 \ Pa[/tex]
Odp. Wywiera ciśnienie p = 500 Pa.