Hej!
Oto Twoja odpowiedź:
Pole trójkąta = a•h/2
zadanie 4
a) a = 2 cm
h = 3 cm
[tex]p = \frac{2cm \times 3cm}{2} = \frac{6cm}{2} = {3cm}^{2} [/tex]
b) a = 4 mm
h = 12 mm
[tex]p = \frac{4mm \times 12mm}{2} = \frac{48mm}{2} = {24mm}^{2} [/tex]
c) a = 9 cm
h = 2 dm = 20 cm
[tex]p = \frac{9cm \times 20cm}{2} = \frac{180cm}{2} = {90cm}^{2} [/tex]
d) a = 2 m = 20 dm
h = 15 dm
[tex]p = \frac{20dm \times 15dm}{2} = \frac{300dm}{2} = {150dm}^{2} [/tex]
Pozdrawiam™
