[tex]dane:\\V = 20 \ cm^{3} = 0,00002 m^{3}\\d = 1000\frac{kg}{m^{3}} \ - \ gestosc \ wody\\g = 10\frac{N}{kg}\\szukane:\\F_{w} = ?\\\\F_{w} = d\cdot g\cdot V\\\\F_{w} = 1000\frac{kg}{m^{3}}\cdot 10\frac{N}{kg}\cdot0,00002 \ m^{3}\\\\F_{w} = 0,2 \ N[/tex]
