Do dzielenia użyłam schematu Hornera
a)
[tex]\begin{array}{c||c|c|cc}&2&-5&-12&\\4&2&3&0&\leftarrow\text{podzielny}\end{array}\\\\\\\cfrac{2x^2-5x-12}{x-4}=2x+3[/tex]
b)
[tex]\begin{array}{c||c|c|c|cc}&1&-2&3&-4&\\-2&1&-4&11&-26&\leftarrow\text{niepodzielny}\end{array}\\\\\\\cfrac{x^3-2x^2+3x-4}{x+2}=x^2-4x+11-\cfrac{26}{x+2}[/tex]
c)
[tex]\begin{array}{c||c|c|c|c|cc}&-2&0&3&0&6&\\3&-2&-6&-15&-45&-129&\leftarrow\text{niepodzielny}\end{array}\\\\\\\cfrac{-2x^4+3x^2+6}{x-3}=-2x^3-6x^2-15x-45-\cfrac{129}{x-3}[/tex]
d)
[tex]\begin{array}{c||c|c|c|cc}&4&8&4&-9&\\-3&4&-4&16&-57&\leftarrow\text{niepodzielny}\end{array}\\\\\\\cfrac{4x^3+8x^2+4x-9}{x+3}=-4x^2-4x+16x-\cfrac{57}{x+3}[/tex]
e)
[tex]\begin{array}{c||c|c|c|cc}&2&-1&3&-4&\\1&2&1&4&0&\leftarrow\text{podzielny}\end{array}\\\\\\\cfrac{2x^3-x^2+3x-4}{x-1}=2x^2+x+4[/tex]
