Odpowiedź:
b)
[tex]\frac{3x-2}{4} = \frac{4x-5}{3} / * 12\\9x - 6 = 16x - 20\\9x - 16x = -20 + 6\\-7x = - 14/:14\\x=2\\[/tex]
d)
[tex]3(1-\frac{x}{3} )=\frac{5x-1}{9} /*9\\27(1-\frac{x}{3} = 5x-1\\27-\frac{27x}{3} = 5x-1/*3\\81-27x= 15x-3\\84= 42x/:42\\x=2[/tex]
