Odpowiedź:
Szczegółowe wyjaśnienie:
a)
[tex](x=2)^{2}+2y=x+11+x^{2} \\x+(y-1)^{2} = -2+y^{2}[/tex]
[tex](x=2)^{2}+2y=x+11+x^{2}\\x=-3+2y[/tex]
podstawiamy za x
[tex](-3+2y+2)^{2} +2y=-3+2y+11+(-3+2y)^{2}[/tex]
liczymy y
y= 2
liczymy x
x= -3+2 * 2= 1
Wynik
x= 1
y=2
b)
[tex]1x-2x^{2} -y+y^{2} =3\\2x-4y^{2} +y-\frac{1}{16} +16\frac{1}{16} =9-4y^{2}[/tex]
[tex]x*(1-2x) - y*(1-y) = (y-\sqrt{2x} )(y+\sqrt{2x} )+3\\2x-4y^{2} +y-\frac{1}{16} +16\frac{1}{16} =9-4y^{2}[/tex]
[tex]x-y=3\\2x-4y^{2} +y-\frac{1}{16} +16\frac{1}{16} =9-4y^{2}[/tex]
[tex]x=3+y\\2x-4y^{2} +y-\frac{1}{16} +16\frac{1}{16} =9-4y^{2}\\[/tex]
Podstawiamy x
[tex]2(3+y)-4y^{2} +y-\frac{1}{16} +16\frac{1}{16} =9-4y^{2}[/tex]
y=[tex]-\frac{13}{3}[/tex]
x= 3[tex]-\frac{13}{3}[/tex] = [tex]-\frac{4}{3\\}[/tex]
