I
[tex]12 \frac{1}{3} - 10 \frac{3}{4} = 12 \frac{4}{12} - 10 \frac{9}{12} = 11 \frac{16}{12} - 10 \frac{9}{12} = 1 \frac{7}{12} = 1 \frac{21}{36} [/tex]
II
[tex] \frac{7}{12} + \frac{5}{6} = \frac{7}{12} + \frac{10}{12} = \frac{17}{12} = 1 \frac{5}{12} = 1 \frac{15}{36} [/tex]
III
[tex]4 \times \frac{17}{36} = \frac{17}{9} = 1 \frac{8}{9} = 1 \frac{32}{36} [/tex]
Odp. Wynik III działania jest największy.
