Odpowiedź :
[tex]4(3x-9)-3(2x-8) = 12x-36-6x+32 = 6x - 4\\\\5x+2(x-7)(x+1) = 5x+2(x^{2}+x-7x-7) = 5x+2(x^{2}-6x-7) = \\=5x+2x^{2}-12x-14 =2x^{2}-7x-14\\\\6-\frac{4a}{2}-6-\frac{12a}{3} = 6-2a-6-4a = -6a[/tex]
[tex]Zadanie\\\\4(3x-9)-3(2x-8)=12x-36-6x+24=6x-12\\\\5x+2(x-7)(x+1)=5x+2(x^{2} +x-7x-7) =5x+2x^{2} -12x-14=\\\\=2x^{2} -7x-14\\\\\frac{6-4a}{2} -\frac{6-12a}{3}=3-2a-2+4a=2a+1[/tex]