[tex]Zadanie\ 2\\\\\mid PQ\mid=8\ m\\\mid QR\mid=16\ m\\\mid RS\mid=12\ m\\\mid DP\mid=?\ m\\\\\frac{\mid QR\mid}{\mid PQ\mid}= \frac{\mid RS\mid}{\mid DP\mid} \\\\\frac{16}{8}=\frac{12}{x} \\\\16x=8\cdot12\\\\16x= 96\ \ \ \mid:16\\\\x=6\ m\\\\Odp.\ Szerokosc\ rzeki\ wynosi\ 6\ m[/tex]
