Hej!
[tex]\frac{x-1}{5}+\frac{3-2x}{4}\leq\frac{3}{5}-\frac{2x+3}{2} \ \ |\cdot20\\\\4(x-1)+5(3-2x)\leq12-10(2x+3)\\\\4x-4+15-10x\leq12-20x-30\\\\-6x+11\leq-20x-18\\\\-6x+20x\leq-18-11\\\\14x\leq-29 \ \ |:14\\\\x\leq-\frac{29}{14}\\\\x\in(-\infty;-\frac{29}{14}\rangle[/tex]
Pozdrawiam! - Julka
