Odpowiedź :
[tex]F = 500 \ N\\S = 0,002 \ m^{2}\\p = ?\\\\p = \frac{F}{S}\\\\p = \frac{500 \ N}{0,002 \ m^{2}} = 250 \ 000 \ \frac{N}{m^{2}} = 250 \ 000 \ Pa = 250 \ kPa\\\\(1 \ kPa = 1000 \ Pa)[/tex]
Odp. Szukane ciśnienie p = 250 kPa.
[tex]F = 500 \ N\\S = 0,002 \ m^{2}\\p = ?\\\\p = \frac{F}{S}\\\\p = \frac{500 \ N}{0,002 \ m^{2}} = 250 \ 000 \ \frac{N}{m^{2}} = 250 \ 000 \ Pa = 250 \ kPa\\\\(1 \ kPa = 1000 \ Pa)[/tex]
Odp. Szukane ciśnienie p = 250 kPa.