Szczegółowe wyjaśnienie:
a)
[tex] \frac{3}{7} - \frac{1}{14} = \frac{6}{14} - \frac{1}{14} = \frac{5}{14} [/tex]
b)
[tex] \frac{3}{20} + \frac{1}{5} = \frac{3}{20} + \frac{4}{20} = \frac{7}{20} [/tex]
c)
[tex] \frac{2}{3} + \frac{1}{5} = \frac{10}{15} + \frac{3}{15} = \frac{13}{15} [/tex]
d)
[tex] \frac{3}{4} - \frac{1}{3} = \frac{9}{12} - \frac{4}{12} = \frac{5}{12} [/tex]
e)
[tex] \frac{4}{5} + \frac{4}{7} = \frac{28}{35} + \frac{20}{35} = \frac{48}{35} = 1 \frac{13}{35} [/tex]
f)
[tex] \frac{4}{8} - \frac{1}{3} = \frac{12}{24} - \frac{8}{24} = \frac{4}{24 } = \frac{1}{6} [/tex]
g)
[tex] \frac{5}{6} + \frac{1}{9} = \frac{15}{18} + \frac{2}{18} = \frac{17}{18} [/tex]
h)
[tex] \frac{3}{9} - \frac{4}{12} = \frac{12}{36} - \frac{12}{36} = 0[/tex]
i)
[tex]3 \frac{1}{7} + 2 \frac{1}{5} = 5( \frac{1}{7} + \frac{1}{5} ) = 5( \frac{12}{35} ) = 5 \frac{12}{35} [/tex]
j)
[tex]10 \frac{6}{11} - 3 \frac{4}{22} = 7( \frac{12}{22} - \frac{4}{22} ) = 7 \frac{8}{22} = 7 \frac{4}{11} [/tex]
