Proszę o pomoc w załączniku

zad. 1
A\B
0,2,4,6,8
B\C
1,3,5,7,9
C\A
brak
zad. 2
[tex] log_{3}(6) \times log_{6}(9) = log_{3}(6) \times log_{6}( {3}^{2} ) = log_{3}(6) \times 2 log_{6}(3) = 1 \times 2 = 2[/tex]
zad. 3
[tex](2x + y {)}^{3} = {(2x)}^{3} + 3( {2x)}^{2} y + 3 \times 2x \times {y}^{3} + {y}^{3} = 8 {x}^{3} + 12 {x}^{2} y + 6x {y}^{2} + {y}^{3} [/tex]