Odpowiedź :
[tex]obliczamy\ wartosc\ wyrazenia:\\\\ 3\frac{4}{5} - 0,6 : \frac{1}{8}=3\frac{4}{5}-\frac{6}{\not{10}^5}*\frac{\not{8}^4}{1}= \frac{19}{5}-\frac{24}{5}=-\frac{5}{5}=-1\\\\polowa\ liczby:\\\\-1:2=-\frac{1}{2}\\\\szescian\ polowy\ tej\ liczby:\\\\(-\frac{1}{2})^3=(-\frac{1}{2})*(-\frac{1}{2})(-\frac{1}{2})=-\frac{1}{8}\\\\odp.\ A[/tex]