Odpowiedź:
Pole całkowite stożka wynosi 96π cm²
Szczegółowe wyjaśnienie:
D = 12 cm
h = 8 cm
D = 2r
2r = 12 cm/2
r = 6 cm
l = [tex]\sqrt{r^{2} +h^{2} }[/tex] = [tex]\sqrt{6^{2} + 8^{2} }[/tex] = [tex]\sqrt{36 + 64}[/tex] = [tex]\sqrt{100}[/tex] = 10 (cm)
[tex]P_{p}[/tex] = πr² = (6 cm)²π = 36π cm²
[tex]P_{b}[/tex] = πrl = 6 cm * 10 cm * π = 60π cm²
[tex]P_{c}[/tex] = [tex]P_{p} + P_{b}[/tex] = 36π cm² + 60π cm² = 96π cm²