Odpowiedź :
Zadanie
1.
3,5b - 2,4c - 0,6c - 0,5b = 3b - 3c
2.
(4a - 7b) - (2a + 3b) = 4a - 7b - 2a - 3b = 2a - 10b
3.
-2x·(x - 5) - 3·(x² + 3x) = -2x² + 10x - 3x² - 9x = - 5x² + x
4.
-2x·(8 - x) - 5·(x² + 3x) = -16x + 2x² - 5x² - 15x = - 3x² - 31x
[tex]\underline{3{,}5\,b}-\underline{\underline{2{,}4\,c}}-\underline{\underline{0{,}6\,c}}-\underline{0{,}5\,b}=(3{,}5-0{,}5)\,b+(-2{,}4-0{,}6)\,c=3\,b-3\,c\\\\\\ (4a-7b)-(2a+3b)=\underline{4a}-\underline{\underline{7b}}-\underline{2a}-\underline{\underline{3b}}=(4-2)a+(-7-3)b=2a-10b\\\\\\-2x(x-5)-3(x^2+3x)=-\underline{2x^2}+\underline{\underline{10x}}-\underline{3x^2}-\underline{\underline{9x}}=\\\\{}\qquad\qquad\qquad\qquad \qquad \qquad \qquad =(-2-3)x^2+(10-9)x=-5x^2+x[/tex]
[tex]-2x(8-x)-5(x^2+3x)=-\underline{16x}+\underline{\underline{2x^2}}-\underline{\underline{5x^2}} -\underline{15x}=\\\\{}\qquad\qquad\qquad\qquad \qquad \qquad \quad =(-16-15)x+(2-5)x^2=-31x-3x^2[/tex]