Odpowiedź:
a. 4a = 4 * [tex]\frac{3}{4}[/tex] = [tex]\frac{4}{1} * \frac{3}{4} = \frac{12}{4} = 3[/tex]
b. 2y = 2 * [tex]\frac{11}{5} = \frac{2}{1} * \frac{11}{5} = \frac{22}{5} = 4\frac{2}{5}[/tex]
c. 2a + b = 2 * [tex]\frac{11}{2} + 3[/tex] = [tex]\frac{2}{1} * \frac{11}{2} + 3 = \frac{22}{2} + 3 = 11 + 3 = 14[/tex]
d. [tex]\frac{1}{4} * h = \frac{1}{4} * 6 = \frac{1}{4} * \frac{6}{1} = \frac{6}{4} = \frac{3}{2} = 1\frac{1}{2}[/tex]
