[tex]a) \ \sqrt{64}-\sqrt[3]{-125} = 8 - (-5) = 8+5 = 13\\\\b) \ 3\sqrt{\frac{1}{25}}+\frac{\sqrt{36}}{3} = 3\cdot\frac{1}{5}+\frac{6}{3} = \frac{3}{5}+2 = 2\frac{3}{5}\\\\c) \ \sqrt[3]{9\cdot\sqrt{9}} = \sqrt[3]{9\cdot3} = \sqrt[3]{27} = 3\\\\d) \ \sqrt{10\sqrt{10\sqrt{100}}} =\sqrt{10\sqrt{10\cdot10}} = \sqrt{10\cdot10} = 10\\\\e) \ \sqrt{100}-\sqrt{64} + \sqrt{100-64} = 10-8+\sqrt{36} = 2+6 = 8\\\\f) \ \sqrt{900}:\sqrt[3]{8}+\sqrt{81} = 30:2 + 9 = 15+9 = 24[/tex]
