Odpowiedź:
zad 1
(4,3+4,7):3=9:3=3
(14,27-5,67):4=8,6:4=2,15
4,8*2,25-42:5=10,8-8,4=2,4
zad 2
a)6,78*0,9=6,102
b)4,15*2,7=11,205
6,78 4,15
*0,9 2,7
------ ---------
6,102 29,05
+8,30
------------
11,205
zad 3
a)[tex]\frac{4}{15}+\frac{3}{10}=\frac{8}{30}+\frac{9}{30}=\frac{17}{30}[/tex]
b)[tex]1\frac{7}{8}+5\frac{3}{10}=1\frac{35}{40}+5\frac{12}{40}=6\frac{47}{40}=7\frac{7}{40}[/tex]
c)[tex]\frac{8}{9}-\frac{5}{6}=\frac{16}{18}-\frac{15}{18}=\frac{1}{18}[/tex]
d)[tex]5\frac{1}{4}-1\frac{6}{7}=5\frac{7}{28}-1\frac{24}{28}=4\frac{35}{28}-1\frac{24}{28}=3\frac{11}{28}[/tex]
e)[tex]1\frac{2}{11}*5=\frac{13}{11}*5=\frac{65}{11}=5\frac{10}{11}[/tex]
f)[tex]1\frac{3}{4}*1\frac{1}{7}=\frac{7}{4}*\frac{8}{7}=2[/tex]
g)[tex]\frac{1}{3}:7=\frac{1}{3}*\frac{1}{7}=\frac{1}{21}[/tex]
h)[tex]1\frac{5}{7}:1\frac{2}{7}=\frac{12}{7}:\frac{9}{7}=\frac{12}{7}*\frac{7}{9}=\frac{4}{3}=1\frac{1}{3}[/tex]
i)[tex]2\frac{8}{9}-2\frac{2}{5}*1\frac{1}{9}=2\frac{8}{9}-\frac{12}{5}*\frac{10}{9}=2\frac{8}{9}-\frac{24}{9}=\frac{26}{9}=\frac{2}{9}[/tex]
j)[tex](1\frac{2}{5}+1\frac{3}{10}):1\frac{1}{5}=(1\frac{4}{10}+1\frac{3}{10}):\frac{6}{5}=\frac{27}{10}*\frac{5}{6}=\frac{9}{4}=2\frac{1}{4}[/tex]
zad 4
a)3,9*3,7=14,43
b)0,39*3,7=1,443
c)0,39*0,37=0,1443
Szczegółowe wyjaśnienie:
