[tex]dane:\\m = 2 \ t = 2 \ 000 \ kg\\h = 10 \ m\\t = 20 \ s\\g = 10\frac{m}{s^{2}} = 10\frac{N}{kg}\\szukane:\\P = ?\\\\Rozwiazanie\\\\P = \frac{W}{t}\\\\W = E_{p} = mgh\\\\W = 2000 \ kg\cdot10\frac{N}{kg}\cdot10 \ m = 200 \ 000 \ J\\\\P = \frac{200 \ 000 \ J}{20 \ s}=10 \ 000 \ W = 10 \ kW\\\\(1 \ kW = 1000 \ W)[/tex]
Odp. Silnik dźwigu musi mieć moc P = 10 kW.
