Hej!
[tex](3 + 2 \sqrt{3} )(2 \sqrt{3} - 3) = \\ = {(2 \sqrt{3} )}^{2} - {3}^{2} = 12 - 9 = 3[/tex]
Pozdrawiam! - Julka
Odpowiedź:
[tex](3+2\sqrt{3})(2\sqrt{3}-3)=(2\sqrt{3}+3)(2\sqrt{3}-3)=(2\sqrt{3})^2-3^2=2^2*(\sqrt{3})^2-9=\\\\=4*3-9=12-9=3\\\\\\Zastosowano\ \ wz\'or\\\\(a-b)(a+b)=a^2-b^2[/tex]
