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3^0/ 3^-1 =

∛√2 =

21^2 x 4^5 x 8^6 =

[(-1 , 4)^-2]^-1 =

4^5 + 4^5 + 4^5 + 4^5 =


Odpowiedź :

Odpowiedź:

[tex]\frac{3^{0} }{3^{-1} } =\frac{1}{\frac{1}{3} } =1:\frac{1}{3} =1*\frac{3}{1} =1*3=3[/tex]

[tex]\sqrt[3]{\sqrt{2} } =\sqrt[3]{2^{\frac{1}{2} } } =(2^{\frac{1}{2})^{\frac{1}{3} } =2^{\frac{1}{2} *\frac{1}{3} } =2^{\frac{1}{6} } =\sqrt[6]{2}[/tex]

[tex]21^{2} *4^{5} *8^{6} =441*(2^{2} )^{5} *(2^{3} )^{6} =\\ =441*2^{10} *2^{18} =441*2^{28} =\\ =441*268 435 456=118380036096[/tex]

[tex][(-1,4)^{-2} ]^{-1} =[(-\frac{14}{10} )^{-2} ]^{-1}=((\frac{10}{14} )^{2} )^{-1}=\\ =\frac{100}{196} ^{-1} =\frac{196}{100} =1\frac{24}{25}[/tex]

[tex]4^{5} +4^{5} +4^{5} +4^{5} =4^{5} (1+1+1+1)=\\ =4^{5} *4=4^{5+1} =4^{6} =4096[/tex]