Odpowiedź :
[tex]dane:\\p = 20 \ Pa = 20 \ \frac{N}{m^{2}}\\S = 1 \ m^{2}}\\szukane:\\F = ?\\\\Rozwiazanie\\\\p = \frac{F}{S} \ \ |\cdot S\\\\F = p\cdot S\\\\F = 20\frac{N}{m^{2}}\cdot1 \ m^{2} = 20 \ N\\\\Odp. \ b)[/tex]
[tex]dane:\\p = 20 \ Pa = 20 \ \frac{N}{m^{2}}\\S = 1 \ m^{2}}\\szukane:\\F = ?\\\\Rozwiazanie\\\\p = \frac{F}{S} \ \ |\cdot S\\\\F = p\cdot S\\\\F = 20\frac{N}{m^{2}}\cdot1 \ m^{2} = 20 \ N\\\\Odp. \ b)[/tex]