Odpowiedź:
[tex]\dfrac{(\frac{7}{10}-1)*(4\frac{1}{3}-3,5)}{1\frac{3}{4}}=\dfrac{(\frac{7}{10}-\frac{10}{10})*(\frac{13}{3}-\frac{35}{10})}{\frac{7}{4}}=\dfrac{-\frac{3}{10}*(\frac{13}{3}-\frac{7}{2})}{\frac{7}{4}}=\\\\\\=\dfrac{-\frac{3}{10}*(\frac{26}{6}-\frac{21}{6})}{\frac{7}{4}}=\dfrac{-\frac{\not3^1}{\not10_{2}}*\frac{\not5^1}{\not6_{2}}}{\frac{7}{4}}=\dfrac{-\frac{1}{4}}{\frac{7}{4}}=-\frac{1}{4}:\frac{7}{4}=-\frac{1}{\not4}*\frac{\not4}{7}=-\frac{1}{7}[/tex]
