[tex]dane:\\S_1 = 1 \ cm^{2}\\F_1 = 2 \ N\\S_2 = 1 \ mm^2} = 0,01 \ cm^{2}\\szukane:\\F_2 = ?\\\\Rozwiazanie\\\\\frac{F_1}{S_1} = \frac{F_2}{S_2}\\\\F_2\cdot S_1 = F_1\cdot S_2 \ \ /:S_1[/tex]
[tex]F_2 = F_1\cdot\frac{S_2}{S_1}\\\\F_2 = 2 \ N\cdot\frac{0,01 \ cm^{2}}{1 \ cm^{2}} = 2 \ N\cdot0,01 = 0,02 \ N[/tex]
Odp. Woda naciska na palec z siłą 0,02 N.
