Odpowiedź:
[tex]K_{x} = (\frac{M_{x}+N_{x}}{2} )\\-4 = (\frac{-12 + N_{x}}{2} )\\-\frac{1}{2} N_{x} = -6 +4\\\frac{1}{2}N_{x} = 2 /*2\\N_{x} = 4[/tex]
[tex]K_{y} = (\frac{M_{y}+N_{y}}{2} )\\5 = (\frac{-8 + N_{y}}{2} )\\-\frac{1}{2} N_{y} = -4 -5\\\frac{1}{2}N_{y} = 9 \ /*2\\N_{y} = 18[/tex]
N=(4,18)
