Odpowiedź :
[tex]dane:\\m = 5 \ kg\\E_{p} = 2 \ 500 \ J = 2 \ 500 \ N\cdot m\\g = 10\frac{N}{kg}\\szukane:\\h = ?\\\\Rozwiazanie\\\\E_{p} = mgh \ \ /:mg\\\\h = \frac{E_{p}}{m\cdot g}\\\\h = \frac{2500 \ N\cdot m}{5 \ kg\cdot10\frac{N}{kg}}\\\\h = 50 \ m[/tex]