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[tex]a) \ 8\frac{6}{13}-6\frac{11}{13} =7\frac{19}{13}-6\frac{11}{13} = 1\frac{8}{13}\\\\b) \ 8\frac{3}{8}+4\frac{5}{6} = 8\frac{9}{24} + 4\frac{20}{24} = 12\frac{29}{24} = 13\frac{5}{24}\\\\c) \ 9\frac{4}{5}-7\frac{2}{3} = 9\frac{12}{15}-7\frac{10}{15}=2\frac{2}{15}[/tex]

[tex]d) \ 1\frac{4}{21}\cdot4\frac{4}{5} = \frac{25}{21}\cdot\frac{24}{5}= \frac{5}{7}\cdot8=\frac{40}{7} = 5\frac{5}{7}\\\\e) \ 6\frac{8}{9}:5\frac{1}{6} = \frac{62}{9}:\frac{31}{6} = \frac{62}{9}\cdot\frac{6}{31} = \frac{2}{3}\cdot2 = \frac{4}{3} = 1\frac{1}{3}[/tex]

Magdago Magdago · Answer 2

Odpowiedź:

[tex]a)\ \ 8\frac{6}{13}-6\frac{11}{13}=7\frac{19}{13}-6\frac{11}{13}=1\frac{8}{13}\\\\b)\ \ 8\frac{3}{8}+4\frac{5}{6}=8\frac{9}{24}+4\frac{20}{24}=12\frac{29}{24}=13\frac{5}{24}\\\\c)\ \ 9\frac{4}{5}-7\frac{2}{3}=9\frac{12}{15}-7\frac{10}{15}=2\frac{2}{15}\\\\d)\ \ 1\frac{4}{21}*4\frac{4}{5}=\frac{\not25^5}{\not21_{7}}*\frac{\not24^8}{\not5_{1}}=\frac{40}{7}=5\frac{5}{7}[/tex]

[tex]e)\ \ 6\frac{8}{9}:5\frac{1}{6}=\frac{62}{9}:\frac{31}{6}=\frac{\not62^2}{\not9_{3} }*\frac{\not6^2}{\not31_{1}}=\frac{4}{3}=1\frac{1}{3}[/tex]