Odpowiedź :
a)
[tex]5(x + 4 + 6y) = 5x + 20 + 30y[/tex]
b)
[tex]4a(2x + 5a - 3) = 6ax + 20 {a}^{2} - 12a [/tex]
c)
[tex]3x(3x - 4y - 5 {x}^{2} ) = 9 {x}^{2} - 12xy - 15 {x}^{3} [/tex]
a)
[tex]5(x + 4 + 6y) = 5x + 20 + 30y[/tex]
b)
[tex]4a(2x + 5a - 3) = 6ax + 20 {a}^{2} - 12a [/tex]
c)
[tex]3x(3x - 4y - 5 {x}^{2} ) = 9 {x}^{2} - 12xy - 15 {x}^{3} [/tex]