[tex]\frac{x}{x}-1 = 1 + \frac{2}{x} - 1\\\\x \neq 0\\D = R \setminus\{0\}\\\\\frac{x}{x} -1-(1+\frac{2}{x}-1) = 0\\\\\frac{x}{x}-1-1-\frac{2}{x}+1 = 0\\\\1-1-1-\frac{2}{x}+1 = 0\\\\-\frac{2}{x} = 0 \ \ |\cdot x\\\\-2 = 0\\\\-2 \neq 0[/tex]
Równanie nie ma rozwiązania.
