Odpowiedź:
zad 1
a = (3 - 3⁻¹)² = (3 - 1/3)² = (2 3/3 - 1/3)² = (2 2/3)² = (8/3)² = 64/9 = 7 1/9
b = (2 2/3)² = (8/3)² = 64/9 = 7 1/9
a = b
Odp: A
zad 2
a)
(2 1/3)³ * (1/7)³ = (2 1/3 * 1/7)³ = (7/3 * 1/7)³ = (1/3)³ = 1/27
b)
(1/2)⁴/(0,125)³ = (1/2)⁴/(1/8)³ = (1/2)⁴/[(1/2)³]³ = (1/2)⁴/(1/2)⁹ = (1/2)⁴⁻⁹ =
= (1/2)⁻⁵ = 2⁵ = 32
zad 3
[(ab⁻²)³ : a⁻¹]/a²b⁻⁴ = (ab⁻⁶ : a⁻¹)/a²b⁻⁴ = (a : a⁻¹ * b⁻⁶)/a²b⁻⁴ =
=(a¹⁻¹ * b⁻⁶)/a²b⁻⁴ = b⁻⁶/a²b⁻⁴ = b⁻⁶⁺⁴/a² = b⁻²/a² = 1/a²b²
