[tex]dane:\\m = 0,13 \ kg\\S = 13 \ cm\times 9 \ cm = 117 \ cm^{2} = 0,0117 \ m^{2}\\g = 10\frac{N}{kg}\\szukane:\\p = ?\\\\Rozwiazanie\\\\p = \frac{F}{S}\\\\F = m\cdot g = 0,13 \ kg\cdot10\frac{N}{kg} = 1,3 \ N\\\\p = \frac{1,3 \ N}{0,0117 \ m^{2}} =111,(1) \ Pa \approx 111 \ Pa[/tex]
