Odpowiedź :
Odpowiedź:
[tex]\left \{ {{a^{2}-b^{2}=-4} \atop {b-a=3}} \right.[/tex]
[tex]\left \{ {{a^{2}-(3+a)^{2}=-4} \atop {b=3+a}} \right.[/tex]
[tex]\left \{ {{a^{2}-(9+6a+a^{2}=-4} \atop {b=3+a}} \right.[/tex]
[tex]\left \{ {{a^{2}-9-6a-a^{2}=-4} \atop {b=3+a}} \right.[/tex]
[tex]\left \{ {{-6a=5} \atop {b=3+a}} \right.[/tex]
[tex]\left \{ {{a=-\frac{5}{6} } \atop {b=2\frac{1}{6} }} \right.[/tex]
a=(-5/6)
b=2 1/6
a+b=[tex]-\frac{5}{6}+2\frac{1}{6}=\frac{8}{6}=1\frac{1}{3}[/tex]
Szczegółowe wyjaśnienie: