Odpowiedź:
[tex]a)\\\\3x+4\ \ \ \ dla\ \ x=3\\\\3x+4=3*3+4=9+4=13\\\\\\3x+4\ \ \ \ dla\ \ x=-2\\\\3x+4=3*(-2)+4=-6+4=-2\\\\\\3x+4\ \ \ \ dla\ \ x=\frac{1}{6}\\\\3x+4=\not3^1*\frac{1}{\not6_{2} }+4=\frac{1}{2}+4=4\frac{1}{2}\\\\\\\\b)\\\\-2x+y^2\ \ \ \ dla\ \ x=2\ \ ,\ \ y=3\\\\-2x+y^2=-2*2+3^2=-4+9=5\\\\\\-2x+y^2\ \ \ \ dla\ \ x=-4\ \ ,\ \ y=5\\\\-2x+y^2=-2*(-4)+5^2=8+25=33\\\\\\-2x+y^2\ \ \ \ dla\ \ x=\frac{5}{8}\ \ ,\ \ y=0,5[/tex]
[tex]-2x+y^2=-\not2^1*\frac{5}{\not8_{4}}+0,5^2=-\frac{5}{4}+(\frac{1}{2})^2=-\frac{5}{4}+\frac{1}{4}=-\frac{4}{4}=-1[/tex]
