Odpowiedź :
Odpowiedź:
[tex]a) - 2 \times b \times ( - 5a) = 10ab \\ b)c \times 2ab \times 3a = 6 {a}^{2} bc \\ c)4y \times ( - 5 {x}^{2} ) \times ( - y) = 20 {x}^{2} {y}^{2} \\ d)b \times ( - 7 {ab}^{2} ) = - 7a {b}^{3} [/tex]
[tex]a) \ -2\cdot b\cdot(-5a) = 10ab\\\\b) \ c\cdot2ab\cdot3a = 6a^{2}bc\\\\c) \ 4y\cdot(-5x^{2})\cdot(-y) = 20x^{2}y^{2}\\\\d) \ b\cdot(-7ab^{2}) = -7ab^{3}[/tex]