Odpowiedź:
[tex]x-2(x+5)=-3(4+x)+8\\\\x-2x-10=-12-3x+8\\\\-x-10=-4-3x\\\\-x+3x=-4+10\\\\2x=6\ \ /:2\\\\x=3[/tex]
[tex]\frac{x}{2}-3(x-2)=-5x+16\\\\\frac{x}{2}-3x+6=-5x+16\ \ /*2\\\\x-6x+12=-10x+32\\\\-5x+10x=32-12\\\\5x=20\ \ /:5\\\\x=4[/tex]
[tex]\frac{x+1}{3}-2(x-1)=\frac{x}{2}-x\\\\\frac{x+1}{3}-2x+2=\frac{x}{2}-x\ \ /*6\\\\2(x+1)-12x+12=3x-6x\\\\2x+2-12x+12=-3x\\\\-10x+14=-3x\\\\-10x+3x=-14\\\\-7x=-14\ \ /:(-7)\\\\x=2[/tex]
