[tex]dane:\\m = 50 \ kg\\r = \frac{d}{2} = \frac{20 \ m}{2} = 10 \ m\\v = 20\frac{m}{s}\\szukane:\\F_{d} = ?\\\\Rozwiazanie\\\\F_{d} = \frac{mv^{2}}{r}\\\\F_{d} = \frac{50 \ kg\cdot(20\frac{m}{s})^{2}}{10 \ m}=2 \ 000 \ N = 2 \ kN\\\\(1 \ kN = 1000 \ N)[/tex]
Odp. Siła dośrodkowa ma wartość Fd = 2 000 N (2 kN).
