Odpowiedź:
[tex]a)\\\\2+\frac{x}{2}=\frac{1-x}{3}\ \ /*6\\\\12+3x=2(1-x)\\\\12+3x=2-2x\\\\3x+2x=2-12\\\\5x=-10\ \ /:5\\\\x=-2[/tex]
[tex]b)\\\\-\frac{x+3}{5}-1=3-\frac{5x}{2}\ \ /*10\\\\-2(x+3)-10=30-25x\\\\-2x-6-10=30-25x\\\\-2x-16=30-25x\\\\-2x+25x=30+16\\\\23x=46\ \ /:23\\\\x=2[/tex]
[tex]c)\\\\\frac{2(x+3)}{9}-4=\frac{2x+3}{6}-x\\\\\frac{2x+6}{9}-4=\frac{2x+3}{6}-x\ \ /*18\\\\2(2x+6)-72=3(2x+3)-18x\\\\4x+12-72=6x+9-18x\\\\4x-60=-12x+9\\\\4x+12x=9+60\\\\16x=69\ \ /:16\\\\x=\frac{69}{16}\\\\x=4\frac{5}{16}[/tex]
[tex]d)\\\\-\frac{2x-1}{9}+\frac{4x-5}{15}=x-5\ \ /*45\\\\-5(2x-1)+3(4x-5)=45x-225\\\\-10x+5+12x-15=45x-225\\\\2x-10=45x-225\\\\2x-45x=-225+10\\\\-43x=-215\ \ /:(-43)\\\\x=5[/tex]
[tex]e)\\\\-\frac{5(x-2)}{2}=5-\frac{3x}{4}\\\\-\frac{5x-10}{2}=5-\frac{3x}{4}\ \ /*4\\\\-2(5x-10)=20-3x\\\\-10x+20=20-3x\\\\-10x+3x=20-20\\\\-7x=0\ \ /:(-7)\\\\x=0[/tex]
[tex]f)\\\\1-[\frac{3(x+5)}{2}+\frac{3x}{5}]=-1\\\\1-(\frac{3x+15}{2}+\frac{3x}{5})=-1\\\\1-\frac{3x+15}{2}-\frac{3x}{5}=-1\ \ /*10\\\\10-5(3x+15)-6x=-10\\\\10-15x-75-6x=-10\\\\-65-21x=-10\\\\-21x=-10+65\\\\-21x=55\ \ /:(-21)\\\\x=-\frac{55}{21}\\\\x=-2\frac{13}{21}[/tex]
