Odpowiedź:
1.
[tex] \sqrt[3]{0.04} \times \sqrt[3]{25} = \sqrt[3]{0.04 \times 25} = \sqrt[3]{1} = 1[/tex]
[tex] \sqrt[3]{1 \frac{1}{8} } \times \sqrt[3]{10 \frac{1}{8} } = \sqrt[3]{ \frac{9}{8} } \times \sqrt[3]{ \frac{81}{8} } = \sqrt[3]{ \frac{9}{8} \times \frac{81}{8} } = \sqrt[3]{ \frac{729}{64} } = \frac{9}{8} [/tex]
[tex](3 + 2 \sqrt{5} )(3 - 2 \sqrt{5} ) = 9 - 6 \sqrt{5} + 6 \sqrt{5} - 20 = 9 - 20 = - 11[/tex]
zad. 2
[tex]średnia = \frac{4 + 16 + 13 + 5 + 7 + 16 + 15 + 4}{8} = \frac{80}{8} = 10[/tex]
[tex]mediana = \frac{1}{2} ( a_{4} + a_{5}) = \frac{1}{2} (5 + 7) = \frac{1}{2} \times 12 = 6[/tex]
[tex]dominata = 4 \: \: i \: \: 16[/tex]
zad. 3
[tex] \frac{x - 6}{2} + \frac{5 - 3x}{4} < 0 \\ 2(x - 6) + 5 - 3x < 0 \\ 2x - 12 + 5 - 3x < 0 \\ - x - 7 < 0 \\ - x < 7 \\ x > - 7 \\ x \: e \: (-7;∞) [/tex]
zad. 4
[tex]V = \frac{1}{3} \pi {r}^{2} h[/tex]
1. r = 6 cm
h=6
[tex]V = \frac{1}{3} \pi {6}^{2} \times 6 = \frac{1}{3} \pi36 \times 6 = \frac{1}{3} \pi216 = 72\pi[/tex]
2. r= 3 cm
h= 12 cm
[tex]V = \frac{1}{3} \pi {3}^{2} \times 12 = \frac{1}{3} \pi9 \times 12 = \frac{1}{3} \pi108 = 36\pi[/tex]
[tex]72\pi - 36\pi = 36[/tex]
