zad 19
Rozwiąż równania

[tex] \frac{3 - x}{2} + \frac{x + 2}{2} = \frac{1}{2} [/tex]
[tex] \frac{1}{4}x - \frac{x - 1}{4} = \frac{1}{4} [/tex]
[tex] \frac{x + 1}{2} + \frac{2x - 2}{3} = \frac{2x - 4}{6} [/tex]
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